2(1[3u+7]1)=68

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Solution for 2(1[3u+7]1)=68 equation:


Simplifying
2(1[3u + 7] * 1) = 68

Reorder the terms:
2(1[7 + 3u] * 1) = 68

Reorder the terms for easier multiplication:
2(1 * 1[7 + 3u]) = 68

Multiply 1 * 1
2(1[7 + 3u]) = 68
2([7 * 1 + 3u * 1]) = 68
2([7 + 3u]) = 68
(7 * 2 + 3u * 2) = 68
(14 + 6u) = 68

Solving
14 + 6u = 68

Solving for variable 'u'.

Move all terms containing u to the left, all other terms to the right.

Add '-14' to each side of the equation.
14 + -14 + 6u = 68 + -14

Combine like terms: 14 + -14 = 0
0 + 6u = 68 + -14
6u = 68 + -14

Combine like terms: 68 + -14 = 54
6u = 54

Divide each side by '6'.
u = 9

Simplifying
u = 9

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